Catapult :: essays research papers

The Ratapult object glass My objective in this project was to produce a rat-trap powered catapult. It has a base of 30 cm by 30 cm, and has a piece of music of overawe trying to escape the farm. The reason they want to escape is because they are being killed and turned into steaks, against there allow. That is why I developed this ratapult, to prevent the cows. The cows also wanted me to ask you to eat more chicken. assumption and DrawingI hypothesize that if I build the ratapult to a 25-degree cant over, and pass the hacky sack at a height of .55m then there will be enough velocity to project the hacky sack exactly quadruplet meters. The ratapult will release the hacky sack with an initial velocity of 5.8 m/s, and as a result the hacky sack will travel 4.0 meters in .75 seconds. partThe first step I took was to paint all of the wood white. by and by that I put wallpaper on the get along that I am going to nail the rat trap to. I then disposed the measuring cup to the rat trap by drilling a mariner in the middle of the measuring cup and then utilise string to attach the cup at both the drilled hole, and the hole at the bottom. because I nailed the rat trap into the board with wallpaper. That board was then nailed into the base. Then I accustomed the stairs to the milk crate. The steps will hold the base of the ratapult at a 25-degree angle. I attached the steps by drilling holes in the bottom of them and then secure them to the milk crate. Then I nailed the board with wallpaper into the back closedown of the base. The base was then nailed into the steps, and glued grass decorations and cardboard cows to the base. The ratapult was completed.Data & ObservationsI found the initial velocity, or Vi, by determination the horizontal velocity, or Vx, and then using the equating Vx = Vi * cos(angle). The angle was 25 degrees, so I input that into the equation also. That made the equation look like5.3 m/s = Vi * cos(25)I dissever both sides by sin(25) , then that gave me an initial velocity of 5.8 m/s. Then I decided to find the Vertical height of the hacky sack, so I used the equation Vy = Vi * sin(angle). Vy stands for initial vertical velocity.